2*(2x^2+x)=4*(6+x^2)

Solution for 2*(2x^2+x)=4*(6+x^2) equation:

2(2x^2+x)=4(6+x^2)

We move all terms to the left:

2(2x^2+x)-(4(6+x^2))=0

We multiply parentheses

-(4(6+x^2))+4x^2+2x=0


We calculate terms in parentheses: -(4(6+x^2)), so:

4(6+x^2)

We multiply parentheses

4x^2+24

Back to the equation:

-(4x^2+24)


We add all the numbers together, and all the variables

4x^2+2x-(4x^2+24)=0

We get rid of parentheses

4x^2-4x^2+2x-24=0

We add all the numbers together, and all the variables

2x-24=0

We move all terms containing x to the left, all other terms to the right

2x=24

x=24/2

x=12